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Question : 7 of 100
Marks:
+1,
-0
Solution:
‌cos(‌)=‌‌⇒‌=‌⇒⋅=3√2Let
=+2‌=2−3‌||2=||2+4||2+4(⋅)‌=4+36+12√2‌=40+12√2‌||2=4||2+9||2−12(−)‌=16+81−36√2‌=97−36√2‌⋅=2||2−6||2+⋅‌=8−54+3√2‌=−46+3√2 ‌|×|=(||||)2−(⋅)2‌=(40+12√2(97−36√2))−(3√2−46)2‌=(3016−276√2)−(2134−276√2)‌=882
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