© examsiri.com
Question : 64 of 100
Marks:
+1,
-0
Solution:
v = λa + μba
=λ(2−+2)+μ(+2−) =(2λ+μ)+(2μ−λ)+(2λ−μ) ∵
v⊥3+2− ⇒
v.(3+2−)=0 ⇒
(2λ+μ)3+2(2μ−λ)−(2λ−μ)=0 ...(i)
⇒
λ=−4μ Also,
v.=19 ⇒9λ−2μ=57...(ii)
Solving Eqs. (i) and (ii),
λ=6,μ=− 2v=2−18+2 |2v|2=441+324+729=1494
© examsiri.com
Go to Question: