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Question : 4 of 100
Marks:
+1,
-0
Solution:
‌⋅[(×)−−] ‌⋅(×)−⋅ −⋅ ...........(i)
‌‌ given ‌×= ‌⇒(×)⋅=⋅ =||2=27 ‌⇒⋅(×)=[] =(×)⋅=27 .........(ii)
‌‌ Now ‌⋅=3−6+3=0 ...........(iii)
‌⋅=3 ‌‌...(iv) (given) ‌ ‌‌ By (i), (ii), (iii) & (iv) ‌ ‌27−0−3=24 ‌
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