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Question : 38 of 100
Marks:
+1,
-0
Solution:
=λ+2−3 =−λ+2 ⇒(−)×((+)×(×))=8−40−24 ⇒((−)⋅(+))(×)=8−40j−24 ⇒8(×)=8−40−24 Now,
×=|| =(4−3λ)−(2λ+3)+(−λ2−2) ⇒λ=1 ∴=+2−3 =−+2 ⇒+=2+−,−=3−5 ⇒(+)×(−)=||=2+10+6 ∴ required answer =4+100+36=140
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