© examsiri.com
Question : 32 of 100
Marks:
+1,
-0
Solution:
[]=⋅(×)‌min.(|u||×|cos‌θ)=−α√3401‌⇒‌‌cos‌θ=−1‌|u|=α‌ (Given) ‌‌|×|=√3401‌×=||‌×=‌i−5αj−3αk‌|×|==√3401‌34α2=3400‌α2=100‌α=10‌‌ (as ‌α>0‌ ) ‌‌ So
‌=λ(‌i−5αj−3αk)‌=‌α2=λ2(1+25α2+9α2)‌100=λ2(1+34×100)‌λ2=‌=‌
© examsiri.com
Go to Question: