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Question : 19 of 100
Marks:
+1,
-0
Solution:
Position vector of the point
P(−1,−2,3),A(−2,1,−3)B(2,4,−2), and
C(−4,2,−1)Then
⋅‌‌×=||‌=(5)−(8+2)+(4+6)‌=5−10+10Now
‌⋅‌=(−−2+3)⋅‌| (−10+10) |
| √(5)2+(−10)2+(10)2 |
‌=‌‌=‌=‌=3
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