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Question : 15 of 100
Marks:
+1,
-0
Solution:
1 and
2 are normal vector to the plane
+,+ and
−,− respectively
1=||=−− 2=||=++ =λ|2×2| =λ||=λ(−2+2) ‌⋅=λ|0+4+2|=6‌⇒λ=1‌=−2+2‌cos‌θ=‌‌cos‌θ=‌=‌‌θ=‌ ‌‌ Now ‌|⋅|2+|×|2=|a|2|b|2‌36+|×b2|=8×9=72‌|×b|2=36‌|×|=6
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