If \overrightarrow{u}, \overrightarrow{v}, \overrightarrow{w} are non-coplanar vectors and p, q are real numbers, then the equality [3 \overrightarrow{u} \overrightarrow{v v} \overrightarrow{w}]-[p \overrightarrow{v} \overrightarrow{w} q \overrightarrow{u}]-[2 \overrightarrow{w} q \overrightarrow{v} q \overrightarrow{u}]=0 \text{ holds for : } [AIEEE 2009]

Correct Answer is : exactly one value of (p,q)

more than two but not all values of (p, q)

Vector Algebra Part 1

Section: Mathematics

Question : 70 of 100

Marks: +1, -0

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are non-coplanar vectors and p,q are real numbers, then the equality
[3

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]−[p

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]−[2

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]=0‌ holds for : ‌

[AIEEE 2009]

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