Let {\P}(\alpha, \beta, \gamma) be the image of the point {\Q}(3,-3,1) in the line \frac{x-0}{1}=\frac{y-3}{1}=\frac{z-1}{-1} and R be the point (2,5,-1). If the area of the triangle {\PQR} is \lambda and \lambda^2=14 {\K}, then {\K} is equal to: [6 Apr 2024 Shift 2]

Three Dimensional Geometry Part 4

Section: Mathematics

Question : 56 of 73

Marks: +1, -0

Let P(α,β,γ) be the image of the point Q(3,−3,1) in the line ‌

x−0

=‌

y−3

=‌

z−1

−1

and R be the point (2,5,−1). If the area of the triangle PQR is λ and λ2=14K, then K is equal to:

[6 Apr 2024 Shift 2]

Go to Question:

Prev Question

Next Question