Three Dimensional Geometry Part 4

Section: Mathematics
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Question : 49 of 73
 
Marks: +1, -0
The shortest distance between the line ‌
x−3
4
=‌
y+7
−11
=‌
z−1
5
and ‌
x−5
3
=‌
y−9
−6
=‌
z+2
1
is:
[9 Apr 2024 Shift 1]
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