Let P be the foot of the perpendicular from the point Q(10,-3,-1) on the line \frac{x-3}{7}=\frac{y-2}{-1}=\frac{z+1}{-2}. Then the area of the right-angled triangle P Q R, where R is the point (3,-2,1), is [23 Jan 2025 Shift 1]

Three Dimensional Geometry Part 4

Section: Mathematics

Question : 44 of 73

Marks: +1, -0

Let P be the foot of the perpendicular from the point Q(10,−3,−1) on the line ‌

x−3

=‌

y−2

−1

=‌

z+1

−2

. Then the area of the right-angled triangle PQR, where R is the point (3,−2,1), is

[23 Jan 2025 Shift 1]

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