Let A be the point of intersection of the lines L_1: \frac{x-7}{1}=\frac{y-5}{0}=\frac{z-3}{-1} and L_2: \frac{x-1}{3}=\frac{y+3}{4}=\frac{z+7}{5}. Let B and C be the points on the lines L_1 and L_2 respectively such that A B=A C=\sqrt{15}. Then the square of the area of the triangle A B C is: [4 Apr 2025 Shift 2]

Three Dimensional Geometry Part 4

Section: Mathematics

Question : 19 of 73

Marks: +1, -0

Let A be the point of intersection of the lines L1:‌

x−7

=‌

y−5

=‌

z−3

−1

and L2:‌

x−1

=‌

y+3

=‌

z+7

.
Let B and C be the points on the lines L1 and L2 respectively such that AB=AC=√15. Then the square of the area of the triangle ABC is:

[4 Apr 2025 Shift 2]

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