Let (\alpha, \beta, \gamma) be the foot of perpendicular from the point (1,2,3) on the line \frac{x+3}{5}=\frac{y-1}{2}=\frac{z+4}{3}. then 19(\alpha+\beta+\gamma) is equal to : [30-Jan-2024 Shift 1]

Three Dimensional Geometry Part 3

Section: Mathematics

Question : 7 of 100

Marks: +1, -0

Let (α,β,γ) be the foot of perpendicular from the point (1,2,3) on the line ‌

x+3

=‌

y−1

=‌

z+4

. then 19(α+β+γ) is equal to :

[30-Jan-2024 Shift 1]

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