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Three Dimensional Geometry Part 3

Section: Mathematics
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Question : 5 of 100
 
Marks: +1, -0
If d1 is the shortest distance between the lines x+1=2y=−12z,x=y+2=6z−6 and d2 is the shortest distance between the lines ‌
x−1
2
=‌
y+8
−7
=‌
z−4
5
,‌
x−1
2
=‌
y−2
1
=‌
z−6
−3
, then the value of ‌
32√3d1
d2
 is :__
[30-Jan-2024 Shift 1]
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