Let the plane P contain the line 2 x+y-z-3=0=5 x-3 y+4 z+9 and be parallel to the line \frac{x+2}{2}=\frac{3-y}{-4}=\frac{z-7}{5} Then the distance of the point {\A}(8,-1,-19) from the plane {\P} measured parallel to the line \frac{ {\x}}{-3}=\frac{ {\y}-5}{4}=\frac{2- {\z}}{-12} is equal to _______ [15-Apr-2023 shift 1]

Three Dimensional Geometry Part 3

Section: Mathematics

Question : 18 of 100

Marks: +1, -0

Let the plane P contain the line 2x+y−z−3=0=5x−3y+4z+9 and be parallel to the line ‌

x+2

=‌

3−y

−4

=‌

z−7

Then the distance of the point A(8,−1,−19) from the plane P measured parallel to the line ‌

−3

=‌

y−5

=‌

2−z

−12

is equal to _______

[15-Apr-2023 shift 1]

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