Three Dimensional Geometry Part 2

Section: Mathematics

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Question : 74 of 100

Marks: +1, -0

If (x,y,z) be an arbitrary point lying on a plane P, which passes through the points (42,0,0),(0,42,0) and (0,0,42), then the value of expression

3+‌

x−11

(y−19)2(z−12)2

+‌

y−19

(x−11)2(z−12)2

+‌

z−12

(x−11)2(y−19)2

−‌

x+y+z

14(x−11)(y−19)(z−12)

is equal to

[16 Mar 2021 Shift 2]

0
3
39
−45

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