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Question : 64 of 100
Marks:
+1,
-0
Solution:
Equation of plane :
|| x−1 | y−0 | z−1 |
| 1−1 | 2 | 1−1 |
| 1−0 | 0−1 | 1+2 |
|=0 ⇒3x−z−2=0 =α+β+γ∥ to
3x−z−2=0 ⇒3α−8=0 .......(1)
⊥+2+3 ⇒α+2β+38=0.......(2)
.(++2)=0 ⇒α+β+28=2 .......(3)
on solving
1,2 & 3 α=1,β=−5,8=3 So
(α−β+8)=81
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