If the shortest distance between the straight lines 3({x}-1)=6({y}-2)=2({z}-1) and4({x}-2)=2({y}-\\lambda)=({z}-3), \\lambda\\in {R} is {1}/{\\sqrt{38}, then the integral value of \\lambda is equal to : [22 Jul 2021 Shift 2]

Three Dimensional Geometry Part 2

Section: Mathematics

Question : 61 of 100

Marks: +1, -0

If the shortest distance between the straight lines 3(x−1)=6(y−2)=2(z−1) and4(x−2)=2(y−λ)=(z−3),λ∈R is

√38

, then the integral value of λ is equal to :

[22 Jul 2021 Shift 2]

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