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Question : 4 of 100
Marks:
+1,
-0
Solution:
‌ Normal to plane ‌=||=(1−a2)−(−a−1)+(1+a)=(1−a)++Distance from
(2,1,4) is
√3 i.e.
⇒|‌| (1−a)+0+4 |
| √(1−a)2+1+1 |
|=√3⇒25+a2−10a=3a2−6a+9⇒2a2+4a−16=0⇒a2+2a−8=0a=2‌ or ‌−4 ∴amax=2
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