Three Dimensional Geometry Part 2

Section: Mathematics

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Question : 13 of 100

Marks: +1, -0

Let ‌

x−2

3

=‌

y+1

−2

=‌

z+3

−1

lie on the plane px−qy+z=5, for some p,q∈R. The shortest distance of the plane from the origin is :

[29-Jun-2022-Shift-2]

√‌
3
109
√‌
5
142
‌
5
√71
‌
1
√142

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