Three Dimensional Geometry Part 1

Section: Mathematics

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Question : 76 of 100

Marks: +1, -0

Let the line ‌‌‌

x−2

3

=‌

y−1

−5

=‌

z+2

2

lie in the plane ‌‌x+3y−αz+β=0. Then (α,β) equals

[AIEEE 2009]

(−6,7)
(5,−15)
(−5,5)
(6,−17)

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