Three Dimensional Geometry Part 1

Section: Mathematics

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Question : 55 of 100

Marks: +1, -0

The distance of the point (1,3,−7) from the plane passing through the point (1,−1,−1) having normal perpendicular to both lines

x−1

1

=y+2/−2=

z−4

3

and

x−2

2

=

y+1

−1

=

z+7

−1

is :-

[Main 2017]

10
√74
20
√74
10
√83
5
√83

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