Statement -1: The variance of first n even natural numbers is \frac{n^2-1}{4} Statement -2 : The sum of first {\n} natural numbers is \frac{n(n+1)}{2} and the sum of squares of first {\n} natural numbers is \frac{n(n+1)(2 n+1)}{6} [AIEEE 2009]

Correct Answer is : Statement- 1 is false, Statement- 2 is true

Statement- 1 is true, Statement- 2 is true; Statement- 2 is a correct explanation for Statement-1

Statement- 1 is true, Statement- 2 is true; Statement- 2 is not a correct explanation for Statement-1

Statement- 1 is true, Statement-2 is false

Statement- 1 is false, Statement- 2 is true

Statistics Part 1

Section: Mathematics

Question : 89 of 100

Marks: +1, -0

Statement −1: The variance of first n even natural numbers is ‌

n2−1

Statement −2 : The sum of first n natural numbers is ‌

n(n+1)

and the sum of squares of first n natural numbers is ‌

n(n+1)(2n+1)

[AIEEE 2009]

Statement- 1 is true, Statement- 2 is true; Statement- 2 is a correct explanation for Statement-1
Statement- 1 is true, Statement- 2 is true; Statement- 2 is not a correct explanation for Statement-1
Statement- 1 is true, Statement-2 is false
Statement- 1 is false, Statement- 2 is true

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