Statistics Part 1

NOTE :
If total no of terms are even then median
=‌

1

2

[‌

n

2

. th term +(‌

n

2

+1) th term]
Here total terms =50, which is even
∴ Median =‌

1

2

[‌

50

2

. th term +(‌

50

2

+1) th term]
=‌

1

2

[25 th term +26 th term ]
=‌

1

2

[25a+26a]
=25.5a
Mean deviation (M.D.) about the median
‌=‌

50 ∑ i=1 ∣xi−‌ Median ‌∣

N

=50‌ (given) ‌
‌∴‌

1

50

[2×|a|×(0.5+1.5+2.5+....24.5)]=50
‌⇒2|a|×‌

25

2

×25=2500
‌⇒|a|=‌

2500

25×25

=4