Statistics Part 1

Let a, b, c, d and e are 5 remaining observations n = 7, Mean = 8, Variance = 16
Sum of observations =7×8=56
Mean of remaining observations =

56−8−6

5

=

42

5

and Variance =

Σx2

n

−(x)2
16=

Σx2

7

−64
⇒Σx2=560
⇒a2+b2+c2+d2+e2=560−82−62 =460
Variance of 5 remaining observations =

460

5

−(

42

5

)2=

536

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