Let 9= {\x}_1 < {\x}_2 < . . . < {\x}_7 be in an A.P. with common difference {\d}. If the standard deviation of {\x}_1, {\x}_2 . . ., {\x}_7 is 4 and the mean is \overline{ {\x}}, then \overline{ {\x}}+ {\x}_6 is equal to : [1-Feb-2023 Shift 2]

Statistics Part 1

Section: Mathematics

Question : 2 of 100

Marks: +1, -0

Let 9=x1<x2<...<x7 be in an A.P. with common difference d. If the standard deviation of x1,x2...,x7 is 4 and the mean is x, then x+x6 is equal to :

[1-Feb-2023 Shift 2]

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