Let {\E}_1 and {\E}_2 be two events such that the conditional probabilities P(E_1 ∣ E_2)=\frac{1}{2}, P(E_2 ∣ E_1)=\frac{3}{4} and P(E_1 \cap E_2)=\frac{1}{8}. Then : [25-Jun-2022-Shift-1]

Correct Answer is : P(E1∩E2′)=P(E1)⋅P(E2)

P(E_1 \cap E_2)=P(E_1) \cdot P(E_2)

P(E_1^{'} \cap E_2^{'})=P(E_1^{'}) \cdot P(E_2)

P(E_1 \cap E_2^{'})=P(E_1) \cdot P(E_2)

P(E_1^{'} \cap E_2)=P(E_1) \cdot P(E_2)

Probability Part 2

Section: Mathematics

Question : 86 of 100

Marks: +1, -0

Let E1 and E2 be two events such that the conditional probabilities P(E1∣E2)=‌

,P(E2∣E1)=‌

and P(E1∩E2)=‌

. Then :

[25-Jun-2022-Shift-1]

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