Probability Part 1

Six faces have numbers {1,2,3,5,7,11}.
Sum of the numbers on top faces of both the sides is less than or equal to 8
Then possible outcomes
(1,1),(1,2),(1,3),(1,5),(1,7)‌→5
(2,1),(2,2),(2,3),(2,5)‌→4
(3,1),(3,2),(3,3),(3,5)‌→4
(5,1),(5,2),(5,3)‌→3
(7,1)‌→1
n(S)=5+4+4+3+1=17
Total number of outcomes n(T)=6×6=36
∴‌‌ Probability =‌

17

36