For the system of linear equations a x+y+z=1, x+a y+z=1, x+y+a z=\beta, which one of the following statements is NOT correct? [1-Feb-2023 Shift 2]

Correct Answer is : It has infinitely many solutions if α=2 and β=−1

It has infinitely many solutions if \alpha=2 and \beta=-1

It has no solution if \alpha=-2 and \beta=1

x+y+z=\frac{3}{4} if \alpha=2 and \beta=1

It has infinitely many solutions if \alpha=1 and \beta=1

Matrices and Determinants Part 3

Section: Mathematics

Question : 57 of 100

Marks: +1, -0

For the system of linear equations ax+y+z=1, x+ay+z=1,x+y+az=β, which one of the following statements is NOT correct?

[1-Feb-2023 Shift 2]

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