The values of \\lambda and \\mu such that the system of equations x+y+z=6,3 x+5 y+5 z=26, {x}+2 {y}+\\lambda{z}=\\mu has no solution, are : [22 Jul 2021 Shift 2]

Correct Answer is : λ=2,µ≠10

Matrices and Determinants Part 2

Section: Mathematics

Question : 50 of 100

Marks: +1, -0

The values of λ and µ such that the system of equations x+y+z=6,3x+5y+5z=26, x+2y+λz=µ has no solution, are :

[22 Jul 2021 Shift 2]

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