Let S=\\left(\begin{array}{cc}-1 & a \ 0 & b) \ a & b \in\{1 & 2 & 3 & . . . .100\\end{array}\} and let T_n=\{A \in S: A^{n(n+1)}=I\}. Then the number of elements in ⋂↙\stackrel{100}{n=1} T_n is [24-Jun-2022-Shift-2]

Matrices and Determinants Part 2

Section: Mathematics

Question : 23 of 100

Marks: +1, -0

Let S={(

−1	a
0	b

);a,b∈{1,2,3,....100}} and let Tn={A∈S:An(n+1)=I}. Then the number of elements in

100

⋂

n=1

Tn is

[24-Jun-2022-Shift-2]

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1	−a+ab
0	b2