Limits, Continuity and Differentiability Part 3

Section: Mathematics

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Question : 38 of 69

Marks: +1, -0

Lim

x⟶0

‌

e−(1+2x)

1

2x

x

is equal to :

[9 Apr 2024 Shift 2]

e
‌
−2
e
0
e−e2

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