Limits, Continuity and Differentiability Part 3

Section: Mathematics

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Question : 15 of 69

Marks: +1, -0

lim

x⟶0+

‌

tan(5(x)

1

3

)‌loge(1+3x2)

(tan−13√x)2(e5(x)‌

4

3

−1)

is equal to

[7 Apr 2025 Shift 1]

‌
1
15
‌
5
3
‌
1
3
1

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