Limits, Continuity and Differentiability Part 2

Section: Mathematics

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Question : 43 of 100

Marks: +1, -0

lim

x→‌

1

√2

‌

sin(cos−1x)−x

1−tan(cos−1x)

is equal to :

[26-Jun-2022-Shift-1]

√2
−√2
‌
1
√2
−‌
1
√2

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