Limits, Continuity and Differentiability Part 1

Section: Mathematics

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Question : 55 of 100

Marks: +1, -0

lim

x→0

(27+x)

1

3

−3

9−(27+x)

1

3

equals to:

[Main 16 April 2018 S1]

1
3
−
1
3
−
1
6
1
6

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