Let f (x) = \{\table -1 , -2 \leq x < 0 ;x^2 - 1 , 0 \leq x \leq 2 and g (x) = |f (x)| + f (|x|) . Then, in the interval (–2, 2), g is :- [11 Jan 2019 Shift 1]

Correct Answer is : not differentiable at one point

not differentiable at two points

not differentiable at one point

Limits, Continuity and Differentiability Part 1

Section: Mathematics

Question : 42 of 100

Marks: +1, -0

Let f (x) = {

−1	−2≤x<0
x2−1	0≤x≤2

and
g (x) = |f (x)| + f (|x|) .
Then, in the interval (–2, 2), g is :-

[11 Jan 2019 Shift 1]

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