Limits, Continuity and Differentiability Part 1

Section: Mathematics

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Question : 36 of 100

Marks: +1, -0

lim

x→1−

√π−√2sin−1x

√1−x

is equal to :

[12 Jan 2019 Shift 2]

1
√2π
√
π
2
√
2
π
√π

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