Limits, Continuity and Differentiability Part 1

Section: Mathematics

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Question : 33 of 100

Marks: +1, -0

Let f:R⇒R be a differentiable function Satisfying f′(3)+f′(2)=0. Then

lim

x⇒0

(

1+f(3+x)−f(3)

1+f(2−x)−f(2)

)

1

x

is equal to

[8 Apr 2019 Shift 2]

1
e
e–1
e2

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