Let f(x)=\int \frac{2 x}{ (x^2+1) (x^2+3) } \dx. If {\f}(3)=\frac{1}{2} (\log _e 5-\log _e 6), then {\f}(4) is equal to [25-Jan-2023 Shift 1]

Correct Answer is : 1∕2(loge17−loge19)

{1}\/{2} (\log _{ {\e}} 17-\log _{ {\e}} 19)

\log _{ {\e}} 17-\log _{ {\e}} 18

\frac{1}{2} (\log _{ {\e}} 19-\log _{ {\e}} 17)

\log _{ {\e}} 19-\log _{ {\e}} 20

Indefinite Integrals

Section: Mathematics

Question : 31 of 89

Marks: +1, -0

Let f(x)=∫‌

(x2+1)(x2+3)

‌dx.
If f(3)=‌

(loge5−loge6), then f(4) is equal to

[25-Jan-2023 Shift 1]

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