Let {\f}: \mathbb{R}-\{0\} \to \mathbb{R} be a function satisfying f (\frac{x}{y}) =\frac{f(x)}{f(y)} for all x, y, f(y) \neq 0. If f^{'}( 1)=2024, then [30-Jan-2024 Shift 2]

Correct Answer is : xf′(x)−2024f(x)=0

{\xf}^{'}( {\x})-2024 {\f}( {\x})=0

{\xf}^{'}( {\x})+2024 {\f}( {\x})=0

{\xf}^{'}( {\x})+ {\f}( {\x})=2024

Differentiation

Section: Mathematics

Question : 15 of 78

Marks: +1, -0

Let ‌‌f:ℝ−{0}→ℝ be a function satisfying f(‌

)=‌

f(x)

f(y)

for all x,y,f(y)≠0. If f′(1)=2024, then

[30-Jan-2024 Shift 2]

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