Differential Equations Part 1

Section: Mathematics

Question : 6 of 100

Marks: +1, -0

Let us consider a curve, y=f(x) passing through the point (−2,2) and the slope of the tangent to the curve at any point (x,f(x)) is given by f(x)+xf′(x)=x2 Then

[27 Aug 2021 Shift 1]

x2+2xf(x)−12=0
x3+2xf(x)+12=0
x3−3xf(x)−4=0
x2+2xf(x)+4=0

Validate

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