Let y=y(x) be the solution of the differential equation, x y'-y=x^{2}(x \cos x+\sin x), x>0 If {y}(\\pi)=\\pi, then {y}"( \frac{\\pi}{2} )+ {y}(\frac{\\pi}{2} ) is equal to : [4 Sep 2020 Shift 1]

1+ \frac{\\pi}{2}+ {\\pi^{2}}/{4}

2+ \frac{\\pi}{2}+ {\\pi^{2}}/{4}

Differential Equations Part 1

Section: Mathematics

Question : 45 of 100

Marks: +1, -0

Let y=y(x) be the solution of the differential equation, xy′−y=x2(x‌cos‌x+sin‌x), x>0 If y(π)=π, then y"(

)+y(

) is equal to :

[4 Sep 2020 Shift 1]

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