Definite Integrals Part 3

Section: Mathematics

© examsiri.com

Question : 38 of 115

Marks: +1, -0

The value of

e4

∫

e2

‌

1

x

(‌

e((logex)2+1)−1

e(logex)2+1)−1+e((6−logex)2+1)−1

)‌dx is

[23 Jan 2025 Shift 1]

1
e2
2
loge2

Go to Question:

Prev Question

Next Question