Definite Integrals Part 3
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Question : 27 of 115
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Let for f ( x ) = 7 tan 8 x + 7 tan 6 x − 3 tan 4 x − 3 tan 2 x I 1 =
f ( x ) dx I 2 =
x f ( x ) dx 7 I 1 + 12 ∕ 2
[22 Jan 2025 Shift 1]
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