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Question : 23 of 115
Marks:
+1,
-0
Solution:
‌I=4‌‌‌dx‌=2‌√3+x2−√1+x2‌dx ‌=2[√3+x2‌dx−√1+x2‌dx]‌=2[(‌x√x2+3+‌‌ln‌|√3+x2+x|)−.‌‌‌‌‌(‌x√1+x2+‌‌ln‌|√1+x2+x|)]01‌=2[(1+‌‌ln‌3−‌‌ln‌√3)−(‌+‌‌ln(√2+1))]‌=2(1+‌‌ln‌3−‌−‌‌ln(√2+1))‌=3‌ln‌√3+2−√2−ln(√2+1)‌I−3‌ln‌√3=2−√2−ln(√2+1)
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