If f(x)=\\begin{array}{c}\\int_{0\end{array} ^{x}(5+|1-t|) d t{,}, x>2 ;5 x+1{, }, x \\leq 2, then [25 Jul 2021 Shift 2]

Correct Answer is : f(x) is continuous but not differentiable at x = 2

f(x) is not continuous at x = 2

f(x) is everywhere differentiable

f(x) is continuous but not differentiable at x = 2

f(x) is not differentiable at x = 1

Definite Integrals Part 2

Section: Mathematics

Question : 74 of 100

Marks: +1, -0

If f(x)={

∫

(5+|1−t|)dt,

x>2

5x+1,

x≤2

, then

[25 Jul 2021 Shift 2]

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