If b_n=\int_0^{\frac{\pi}{2}} \frac{\cos ^2 n x}{\sin x} d x, n \in N, then [25-Jun-2022-Shift-2]

Correct Answer is : 1b3−b2,1b4−b3,1b5−b4 are in an A.P. with common difference −2

b_3-b_2, b_4-b_3, b_5-b_4 are in A.P. with common difference -2

\frac{1}{b_3-b_2}, \frac{1}{b_4-b_3}, \frac{1}{b_5-b_4} are in an A.P. with common difference 2

b_3-b_2, b_4-b_3, b_5-b_4 are in a G.P.

\frac{1}{b_3-b_2}, \frac{1}{b_4-b_3}, \frac{1}{b_5-b_4} are in an A.P. with common difference -2

Definite Integrals Part 2

Section: Mathematics

Question : 46 of 100

Marks: +1, -0

If bn=

∫

‌

cos2nx

sin‌x

dx,n∈N, then

[25-Jun-2022-Shift-2]

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