Let [t] denote the greatest integer less than or equal to {\t}. Then, the value of the integral \int_0^1[-8 x^2+6 x-1] d x is equal to [28-Jun-2022-Shift-1]

Correct Answer is : √17−138

Definite Integrals Part 2

Section: Mathematics

Question : 38 of 100

Marks: +1, -0

Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral

∫

1[−8x2+6x−1]dx is equal to

[28-Jun-2022-Shift-1]

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