Definite Integrals Part 1

Section: Mathematics

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Question : 62 of 100

Marks: +1, -0

For x∊R,x≠0, if y(x) is a differentiable function such that x‌

x

∫

1

y(t)dt=(x+1)‌

x

∫

1

ty(t)dt, then y(x) equals :
(where C is a constant.)

[Main 10 Apr 2016]

C
x
e−
1
x
C
x2
e−
1
x
C
x3
e−
1
x
Cx3e
1
x

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