The integral \int^{\pi/4}_{\pi/6} \frac{dx}{sin2x(\tan^5x+\cot^5x)} equals : [11 Jan 2019 Shift 2]

Correct Answer is : 110(π4−tan−1(19√3))

1/{10} (\pi/4-\tan^{-1}(1/{9\sqrt3}))

1/{5} (\pi/4-\tan^{-1}(1/{3\sqrt3}))

Definite Integrals Part 1

Section: Mathematics

Question : 44 of 100

Marks: +1, -0

The integral

∫

sin2x(tan5x+cot5x)

equals :

[11 Jan 2019 Shift 2]

Go to Question:

Prev Question

Next Question